<math> Volumen\ der\ F\ddot{u}llk\ddot{o}rper = 14\ m^2 \div 320\ \frac{m^2}{m^3} = 0,044\ m^3 = 44\ l </math>
R e q u i r e d v o l u m e o f f l o a t i n g e l e m e n t s = 14 m 2 ÷ 320 m 2 m 3 = 0.044 m 3 = 44 L {\displaystyle Required\ volume\ of\ floating\ elements=14\ m^{2}\div 320\ {\frac {m^{2}}{m^{3}}}=0.044\ m^{3}=44\ L}
