R e q u i r e d v o l u m e o f f l o a t i n g e l e m e n t s = 14 m 2 ÷ 320 m 2 m 3 = 0.044 m 3 = 44 L {\displaystyle Required\ volume\ of\ floating\ elements=14\ m^{2}\div 320\ {\frac {m^{2}}{m^{3}}}=0.044\ m^{3}=44\ L}