<math> Zulu\mathit{ft}beda\mathit{rf} = 3.125\ \frac{mg}{min} \div 1000^2 \div 0,2769\ \frac{kg}{m^3} \times 1000\ \frac{l}{m^3} = 11,29\ \frac{l}{min} </math>
I n l e t a i r r e q u i r e m e n t = 3 , 125 m g m i n ÷ 1000 2 ÷ 0.2769 k g m 3 × 1000 L m 3 = 11.29 L m i n {\displaystyle Inlet\ air\ requirement=3,125\ {\frac {mg}{min}}\div 1000^{2}\div 0.2769\ {\frac {kg}{m^{3}}}\times 1000\ {\frac {L}{m^{3}}}=11.29\ {\frac {L}{min}}}
