<math> Fl\ddot{a}chenbeda\mathit{rf} = 0,056\ \frac{kgBSB}{Tag} \div 0,004\ \frac{kgBSB}{m^2 \cdot Tag} = 14\ m^2 </math>
R e q u i r e d s u r f a c e a r e a = 0.056 k g B O D d ÷ 0.004 k g B O D m 2 ⋅ d = 14 m 2 {\displaystyle Required\ su{\mathit {rf}}ace\ area=0.056\ {\frac {kgBOD}{d}}\div 0.004\ {\frac {kgBOD}{m^{2}\cdot d}}=14\ m^{2}}
